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90=-x+x^2
We move all terms to the left:
90-(-x+x^2)=0
We get rid of parentheses
-x^2+x+90=0
We add all the numbers together, and all the variables
-1x^2+x+90=0
a = -1; b = 1; c = +90;
Δ = b2-4ac
Δ = 12-4·(-1)·90
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*-1}=\frac{-20}{-2} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*-1}=\frac{18}{-2} =-9 $
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